$a. \dfrac{11}{7}-\dfrac{3}{5}x=\dfrac{3}{5} \\⇔\dfrac{3}{5}x=\dfrac{11}{7}-\dfrac{3}{5} \\⇔\dfrac{3}{5}x=\dfrac{34}{35} \\⇔x=\dfrac{34}{35}:\dfrac{3}{5} \\⇔x=\dfrac{34}{21} \\b.\dfrac{3}{4}x+\dfrac{1}{2}=\dfrac{7}{2} \\⇔\dfrac{3}{4}x=\dfrac{7}{2}-\dfrac{1}{2} \\⇔\dfrac{3}{4}x=3 \\⇔x=3:\dfrac{3}{4} \\⇔x=4 \\c.\dfrac{5}{3}+\dfrac{7}{6}:\bigg(x-3\dfrac{1}{5}\bigg)=\dfrac{3}{4} \\⇔\dfrac{7}{6}:\bigg(x-\dfrac{16}{5}\bigg)=\dfrac{-11}{12} \\⇔x-\dfrac{16}{5}=\dfrac{-14}{11} \\⇔x=\dfrac{106}{55} \\d.x.\dfrac{3}{5}+x.\dfrac{2}{7}=\dfrac{31}{70} \\⇔x\bigg(\dfrac{3}{5}+\dfrac{2}{7}\bigg)=\dfrac{31}{70} \\⇔x.\dfrac{31}{35}=\dfrac{31}{70} \\⇔x=\dfrac{1}{2}$
