$(\dfrac{1}{11}-\dfrac{5}{45}):\dfrac{2018}{2017}+(-\dfrac{40}{45}+\dfrac{10}{11}):\dfrac{2018}{2017}$
$=(\dfrac{1}{11}-\dfrac{1}{45}).\dfrac{2017}{2018}+(-\dfrac{40}{45}+\dfrac{10}{11}).\dfrac{2017}{2018}$
$=\dfrac{2017}{2018}.[(\dfrac{1}{11}-\dfrac{5}{45})+(-\dfrac{40}{45}+\dfrac{10}{11})]$
$=\dfrac{2017}{2018}.[\dfrac{1}{11}-\dfrac{5}{45}-\dfrac{40}{45}+\dfrac{10}{11}]$
$=\dfrac{2017}{2018}.[(\dfrac{1}{11}+\dfrac{10}{11})+(-\dfrac{5}{45}-\dfrac{40}{45})]$
$=\dfrac{2017}{2018}.[1-1]=\dfrac{2017}{2018}.0=0$