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`x/4=y/3`
`=> x/4 . 1/2 = y/3 . 1/2`
`=> x/8=y/6` (1)
`y/6=z/11` (2)
(1)(2) `=> x/8=y/6=z/11`
Đặt `x/8=y/6=z/11=k(k \ne 0)`
`=>x=8k, y=6k, z=11k`
`xyz=-528`
`=> 8k . 6k . 11k = -528`
`=> 528k^3 = -528`
`=> k^3=-1`
`=> k=-1`
Do đó :
`x=8.(-1)=-8`
`y=6.(-1)=-6`
`z=11.(-1)=-11`
Vậy `(x;y;z)=(-8;-6;-11)`