Đáp án:
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Giải thích các bước giải:
$C=\left(\dfrac{12}{35}-\dfrac67+\dfrac{18}{14}\right):\dfrac{6}{-7}-\dfrac{-2}5-1\\\Rightarrow C=\left(\dfrac{-18}{35}+\dfrac{18}{14}\right):\dfrac{-6}{7}+\dfrac25-1\\\Rightarrow C=\dfrac{27}{35}:\dfrac{-6}{7}+\dfrac25-1\\\Rightarrow C=\dfrac{-9}{10}+\dfrac25-1\\\Rightarrow C=\dfrac{-1}{2}-1\\\Rightarrow C=\dfrac{-3}{2}\\G=\dfrac{\left(\dfrac{-5}{7}-\dfrac79+\dfrac{9}{11}-\dfrac{11}{13}\right)\!.\!\left(3-\dfrac34\right)}{\left(\dfrac{10}{21}+\dfrac{14}{27}-\dfrac{6}{11}+\dfrac{22}{39}\right):\left(2-\dfrac23\right)}\\\Rightarrow G=\dfrac{\left(\dfrac{-15}{21}+\dfrac{-21}{27}-\dfrac{-9}{11}+\dfrac{-33}{39}\right)\!.\!\left(3-\dfrac34\right)}{\left(\dfrac{10}{21}+\dfrac{14}{27}-\dfrac{6}{11}+\dfrac{22}{39}\right):\left(2-\dfrac23\right)}\\\Rightarrow G=\dfrac{\dfrac{-3}{2}\cdot\left(\dfrac{10}{21}+\dfrac{14}{27}-\dfrac{6}{11}+\dfrac{22}{39}\right)\cdot\dfrac94}{\left(\dfrac{10}{21}+\dfrac{14}{27}-\dfrac{6}{11}+\dfrac{22}{39}\right):\dfrac43}\\\Rightarrow G=\dfrac{\dfrac{-3}{2}\cdot\dfrac94}{\dfrac34}\\\Rightarrow G=\dfrac{-3}{2}\cdot3\\\Rightarrow G=\dfrac{-9}{2}$
