Em tham khảo nha :
\(\begin{array}{l}
8)\\
a)\\
CaC{O_3} \to CaO + C{O_2}\\
{n_{C{O_2}}} = \dfrac{{3,36}}{{22,4}} = 0,15mol\\
{n_{CaC{O_3}}} = {n_{C{O_2}}} = 0,15mol\\
{m_{CaC{O_3}}} = 0,15 \times 100 = 15g\\
b)\\
C1:\\
{n_{CaO}} = {n_{C{O_2}}} = 0,15 \times 56 = 8,4g\\
C2:\\
\text{Theo định luật bảo toàn khối lượng ta có :}\\
{m_{CaC{O_3}}} = {m_{CaO}} + {m_{C{O_2}}}\\
\Rightarrow {m_{CaO}} = 15 - 0,15 \times 44 = 8,4g\\
9)\\
a)\\
C{O_2} + 2NaOH \to N{a_2}C{O_3} + {H_2}O\\
{n_{C{O_2}}} = \dfrac{{22}}{{44}} = 0,5mol\\
{n_{N{a_2}C{O_3}}} = {n_{C{O_2}}} = 0,5mol\\
{m_{N{a_2}C{O_3}}} = 0,5 \times 106 = 53g\\
H = \dfrac{{{m_{td}}}}{{{m_{N{a_2}C{O_3}}}}} \times 100\% = \dfrac{{50}}{{53}} \times 100\% = 94,3\%
\end{array}\)
