Đáp án:
9. 1,65m/s2
10.176,32N
11. 10N
Giải thích các bước giải:
9. \(\begin{array}{l}
{F_{TD}} = G.\frac{{{M_{TD}}}}{{R_{TD}^2}}\\
{F_{MT}} = G.\frac{{{M_{MT}}}}{{R_{MT}^2}} = G.\frac{{{M_{TD}}.3,{7^2}}}{{R_{TD}^2.81}} = 9,8.\frac{{3,{7^2}}}{{81}} = 1,65(m/{s^2})
\end{array}\)
10. \(\begin{array}{l}
{F_{TD}} = G.\frac{{{M_{TD}}}}{{R_{TD}^2}}\\
{F_{SH}} = G.\frac{{{M_{SH}}}}{{R_{SH}^2}} = G.\frac{{{M_{TD}}.{{(\frac{{100}}{{53}})}^2}}}{{R_{TD}^2.\frac{{100}}{{11}}}} = 9,8.\frac{{{{(\frac{{100}}{{53}})}^2}}}{{\frac{{100}}{{11}}}} = 3,84(m/{s^2})
\end{array}\)
\(\begin{array}{l}
{P_{TD}} = {g_{TD}}.m\\
{P_{SH}} = {g_{SH}}.m\\
\Rightarrow {P_{SH}} = \frac{{{P_{TD}}.{g_{SH}}}}{{{g_{TD}}}} = \frac{{450.3,84}}{{9,8}} = 176,32(N)
\end{array}\)
11. \(\begin{array}{l}
{g_{MT}} = \frac{1}{6}{g_{TD}} = \frac{5}{3}(m/{s^2})\\
{P_{MT}} = {g_{MT}}.m = 6.\frac{5}{3} = 10(N)
\end{array}\)
