$a,\frac{3x^2+7x-10}{x}=0$
$⇒3x^2+7x-10=0$
$⇒3x^2-3x+10x-10=0$
$⇒3x(x-1)+10(x-1)=0$
$⇒(3x+10)(x-1)=0$
\(\left[ \begin{array}{l}3x+10=0⇒3x=-10⇒x=\frac{-10}{3}\\x-1=0⇒x=1\end{array} \right.\)
$b,\frac{4x-17}{2x^2+1}=0$
$⇒4x-17=0$
$⇒4x=17$
$⇒x=\frac{17}{4}$
$c,d$ làm tương tự
$e,\frac{2x-5}{x+5}=3$
$⇒2x-5=3(x+5)$
$⇒2x-5=3x+15$
$⇒x=-20$