Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}
\left\{ \begin{array}{l}
x = \frac{{3 + 2y}}{m}\\
\frac{{9 + 6y}}{m} + my = 4
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x = \frac{{3 + 2y}}{m}\\
9 + 6y + {m^2}y = 4m
\end{array} \right.\\
\to \left\{ \begin{array}{l}
y = \frac{{4m - 9}}{{6 + {m^2}}}\\
x = \frac{{3 + 2y}}{m} = \frac{{3 + 2.\frac{{4m - 9}}{{6 + {m^2}}}}}{m} = \frac{{18 + 3{m^2} + 8m - 18}}{{m\left( {6 + {m^2}} \right)}}
\end{array} \right.\\
\to \left\{ \begin{array}{l}
y = \frac{{4m - 9}}{{6 + {m^2}}} < 0\\
x = \frac{{3m + 8}}{{6 + {m^2}}} > 0
\end{array} \right. \to \left\{ \begin{array}{l}
4m - 9 < 0\\
3m + 8 > 0
\end{array} \right.\\
\to \left\{ \begin{array}{l}
m < \frac{9}{4}\\
m > \frac{{ - 8}}{3}
\end{array} \right. \to \frac{{ - 8}}{3} < m < \frac{9}{4}
\end{array}\)
