~ Bạn tham khảo ~
Bài 1 :
`a, [ ( 2/5 )^10 ]^5 : [ ( 2/5 )^4 ]^12`
`= ( 2/5 )^50 : ( 2/5 )^48`
`= (2/5)^[50-48]`
`= ( 2/5 )^2`
`= 4/25`
`b,( 2/3 )^2 + | ( - 5 )/6 | : 0,25`
`= 4/9 + 5/6 : 1/4`
`= 4/9 + 10/3`
`= 34/9`
Bài 2 :
`a, ( 3/5 )^8 . x = ( 3/5 )^10`
`=> x = (3/5)^10 : (3/5)^8`
`=> x = (3/5)^[10-8]`
`=> x = (3/5)^2`
`=> x = 9/25`
Vậy `x=9/25`
`b, ( - 3 )/4 + x = ( ( - 1 )/2 )^2`
`=> [-3]/4 + x = 1/4`
`=> x = 1/4 + 3/4`
`=> x = 4/4`
`=> x = 1`
Vậy `x=1`
