Bài 1 :
$\dfrac{5x-2}{-5+3x} = \dfrac{3}{-2}$ $\bigg(x \neq \dfrac{5}{3} \bigg) $
$ ⇔-2.(5x-2)=3.(-5+3x)$
$⇔-10x+4=-15+9x$
$⇔19x = 19$
$⇔x=1$ ( Thỏa mãn )
b) $\dfrac{15-3x}{-4} = \dfrac{36}{3x-15}$ $(x \neq 5) $
$⇔(3x-15)^2 = 4.36 =144 $
$⇔\left[ \begin{array}{l}3x-15=12\\3x-15=-12\end{array} \right.$
$⇔\left[ \begin{array}{l}x=9\\x=1\end{array} \right.$