Đáp án:
10)
C
12)
B
Giải thích các bước giải:
\(\begin{array}{l}
10)\\
{m_X} = 5,312 \times {10^{ - 23}}g\\
1u = 1,67 \times {10^{ - 24}}g\\
{M_X} = \dfrac{{{m_X}}}{{1u}} = \dfrac{{5,312 \times {{10}^{ - 23}}}}{{1,67 \times {{10}^{ - 24}}}} = 32u\\
\Rightarrow X:\text{lưu huỳnh}(S)\\
12)\\
{M_C} = 12dvC\\
1u = \dfrac{{{m_C}}}{{{M_C}}} = \dfrac{{1,9926 \times {{10}^{ - 23}}}}{{12}} = 1,6605 \times {10^{ - 24}}g\\
{M_{Al}} = 27dvC\\
{m_{Al}} = 1u \times {M_{Al}} = 1,6605 \times {10^{ - 24}} \times 27 = 4,48 \times {10^{ - 23}}g
\end{array}\)
