Bạn tham khảo:
$a/$
$Ba(OH)_2 \to Ba^{2+}+2OH^{-}$
$[Ba^{2+}]=0,1M$
$[OH^{-}]=0,1.2=0,2M$
$b/$
$c/$
$[Na^{+}]=0,1.1+0,02.2+0,3=0,44M$
$d/$
$n_{NaCl}=0,4(mol)
$CM_{NaCl}=\frac{0,4}{0,4}=1M$
$NaCl \to Na^{+} +Cl^{-}$
$[Na^{+}]=[Cl^{-}]=1M$
$n_{CaCl_2}=0,1(mol)$
$CM_{CaCl_2}=\frac{0,1}{0,4}=0,25M$
$CaCl_2 \to Ca^{2+} +2Cl^{-}$
$[Ca^{2+}]=0,25M$
$[Cl^{-}]=0,25.2=0,5M$
