$\vec{AB}=(-6; 2)=\vec{u}$
$⇒\vec{n}=(2; 6)$
$⇒$PTTQ: $2(x-3)+6(y-2)=0$
$⇔2x+6y-18=0 ⇔x+3y-9=0$
Vậy PTTQ là: $x+3y-9=0$
Đáp án:
Giải thích các bước giải:pttq ; 2x + 6y - 18
Câu in đậm dưới đây là câu rút gọn hay câu sai cấu trúc cú pháp? Vì sao?
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