Đáp án:
\( {m_{{C_2}{H_5}OH}} = 8,1778{\text{ kg}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\({({C_6}{H_{10}}{O_5})_n} + n{H_2}O\xrightarrow{{axit}}n{C_6}{H_{12}}{O_6}\)
\({C_6}{H_{12}}{O_6}\xrightarrow{{men}}2{C_2}{H_5}OH + 2C{O_2}\)
\({n_{{C_6}{H_{10}}{O_5}}} = \frac{{18}}{{162}} = \frac{1}{9}{\text{ kmol}} = {n_{{C_6}{H_{12}}{O_6}{\text{ lt}}}}\)
\( \to {n_{{C_2}{H_5}OH{\text{ lt}}}} = 2{n_{{C_6}{H_{12}}{O_6}}} = \frac{1}{9}.2 = \frac{2}{9}{\text{ kmol}}\)
\( \to {n_{{C_2}{H_5}OH}} = \frac{2}{9}.80\% = \frac{8}{{45}}{\text{ kmol}}\)
\( \to {m_{{C_2}{H_5}OH}} = \frac{8}{{45}}.46 = 8,1778{\text{ kg}}\)
