Đáp án: `1/6`
Giải thích các bước giải:
`lim_{x->1} \frac{\sqrt{x²+8}-3}{2x-2}`
`= lim_{x->1}\frac{x²+8-9}{2(x-1)(\sqrt{x²+8}+3)}`
`= lim_{x->1}\frac{(x-1)(x+1)}{2(x-1)(\sqrt{x²+8}+3)}`
`= lim_{x->1}\frac{x+1}{2.(\sqrt{x²+8}+3)}`
`= \frac{1+1}{2.(\sqrt{1²+8}+3)}`
`= \frac{2}{12}` `=1/6`