Đáp án:
lim=-4
Giải thích các bước giải:
\(\begin{array}{*{20}{l}}
{\mathop {\lim }\limits_{x \to {\rm{ \;}} - 5} \frac{{{x^2} + 2x - 15}}{{2x + 10}}}\\
{{\rm{\;}} = \mathop {\lim }\limits_{x \to {\rm{ \;}} - 5} \frac{{\left( {x - 3} \right)\left( {x + 5} \right)}}{{2\left( {x + 5} \right)}}}\\
{ = \mathop {\lim }\limits_{x \to {\rm{ \;}} - 5} \frac{{\left( {x - 3} \right)}}{2}}\\
{ = {\rm{ \;}}\frac{{ - 5 - 3}}{2} = {\rm{ \;}} - 4}
\end{array}\)
