Đáp án:
$\widehat{P_{2}}$ `=` $\widehat{P_{4}}$ `=` $60^{o}$ ; $\widehat{P_{3}}$ `=` $120^{o}$
$\widehat{Q_{2}}$ `=` $\widehat{Q_{4}}$ `=` $100^{o}$ ; $\widehat{Q_{3}}$ `=` $80^{o}$
Giải thích các bước giải:
+ $\widehat{P_{1}}$ `=` $\widehat{P_{3}}$ `=` $120^{o}$ ( Hai góc đối đỉnh )
Ta có : $\widehat{P_{1}}$ + $\widehat{P_{2}}$ = $180^{o}$ ( Hai góc kề bù )
`=>` $120^{o}$ `+` $\widehat{P_{2}}$ `=` $180^{o}$
`=>` $\widehat{P_{2}}$ `=` $60^{o}$
Ta thấy : $\widehat{P_{2}}$ `=` $\widehat{P_{4}}$ `=` $60^{o}$ ( Hai góc đối đỉnh )
`+` $\widehat{Q_{1}}$ `=` $\widehat{Q_{3}}$ `=` $80^{o}$ ( Hai góc đối đỉnh )
Ta có : $\widehat{Q_{1}}$ `+` $\widehat{Q_{2}}$ `=` $180^{o}$ ( Hai góc kề bù )
`=>` $80^{o}$ `+` $\widehat{Q_{2}}$ `=` $180^{o}$
`=>` $\widehat{Q_{2}}$ `=` $100^{o}$
Ta thấy : $\widehat{Q_{2}}$ `=` $\widehat{Q_{4}}$ `=` $100^{o}$ ( Hai góc đối đỉnh )
Vậy $\widehat{P_{2}}$ `=` $\widehat{P_{4}}$ `=` $60^{o}$ ; $\widehat{P_{3}}$ `=` $120^{o}$
$\widehat{Q_{2}}$ `=` $\widehat{Q_{4}}$ `=` $100^{o}$ ; $\widehat{Q_{3}}$ `=` $80^{o}$
