Giải thích các bước giải :
Câu 1 :
`a)2021^0+5×3^2-2^8:2^6-2^(2)×13`
`=1+5×9-2^2-4×13`
`=1+45-4-52`
`=-10`
`b)(-37)+44+(-15)+37+(-40)+56`
`=(37-37)+(44+56)-(15+40)`
`=0+100-55`
`=45`
`c)134×34+73×134-7×134-300`
`=134(34+73-7)-300`
`=134×100-300`
`=13400-300`
`=13100`
`d)|-35|+(68-35)-(68-120)`
`=35+68-35-68+120`
`=(35-35)+(68-68)+120`
`=0+0+120`
`=120`
`e)54+(-37)+58-24+(-63)+(-58)`
`=54-37+58-24-63-58`
`=(54-24)+(58-58)-(37+63)`
`=30+0-100`
`=-70`
Câu 2 :
`a)72-(x+35)=26`
`<=>x+35=72-26`
`<=>x+35=46`
`<=>x=46-35`
`<=>x=11`
Vậy `x=11`
`b)164-6(x+1)=80`
`<=>6(x+1)=164-80`
`<=>6(x+1)=84`
`<=>x+1=84:6`
`<=>x+1=14`
`<=>x=14-1`
`<=>x=13`
Vậy `x=13`
`c)128:(3x-22)=6`
`<=>3x-22=128:6`
`<=>3x-22=(128)/6`
`<=>3x=(128)/6+22`
`<=>3x=(64)/3+(66)/3`
`<=>3x=(64+66)/3`
`<=>3x=(130)/3`
`<=>x=(130)/3:3`
`<=>x=(130)/3×1/3`
`<=>x=(130)/9`
Vậy `x=(130)/9`
`d)|x:3|-6=8`
`<=>|x:3|=8+6`
`<=>|x:3|=14`
`<=>`\(\left[ \begin{array}{l}x:3=14\\x:3=-14\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=14×3\\x=-14×3\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=42\\x=-42\end{array} \right.\)
Vậy `x=±42`
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