A.\({\log _{54}}168 = \frac{{ab +1}}{{8a-5ab}}\)
B.\({\log _{54}}168 = \frac{{ab +1}}{{8a+5ab}}\)
C.\({\log _{54}}168 = \frac{{ab -1}}{{8a+5ab}}\)
D.\({\log _{54}}168 = \frac{{ab -1}}{{8a-5ab}}\)

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