Đáp án:
$\begin{array}{l}
\left( {m - 1} \right)x + 1 - {m^2} = 0\\
\Rightarrow \left( {m - 1} \right)x - \left( {{m^2} - 1} \right) = 0\\
\Rightarrow \left( {m - 1} \right)x - \left( {m - 1} \right)\left( {m + 1} \right) = 0\\
\Rightarrow \left( {m - 1} \right)\left( {x - m - 1} \right) = 0\\
\Rightarrow \left[ \begin{array}{l}
m = 1\\
x = m + 1
\end{array} \right.
\end{array}$