1/
a/$C_2H_5OH+CH_3COOH \buildrel{{t^o,H^+}}\over\longleftrightarrow CH_3COOC_2H_5+H_2O$
b/$2CH_3OH+COOH-COOH \buildrel{{t^o,H^+}}\over\longleftrightarrow H_3COOC-COOCH_3+2H_2O$
c/$C_2H_2+COOH-COOH$: không phản ứng
d/$C_2H_2+C_2H_2 \buildrel{{NH4Cl,CuCl2,t^o}}\over\longrightarrow C_4H_4$
2/
$CaC_2+2H_2O \to Ca(OH)_2+C_2H_2$
$3C_2H_2 \buildrel{{C, t^o}}\over\longrightarrow C_6H_6$
$C_6H_6+Cl_2 \buildrel{{Fe}}\over\rightarrow C_6H_5Cl+HCl$
$C_6H_5Cl+NaOH \to C_6H_5OH+NaCl$
$C_6H_5OH+3Br_2 \to C_6H_2Br_3OH+3HBr$
$2C_2H_2 \buildrel{{NH4Cl,CuCl2,t^o}}\over\longrightarrow C_4H_4$
$C_4H_4+H_2 \buildrel{{Pb,PdCO3, t^o}}\over\longrightarrow C_4H_6$
$nCH_2=CH-CH=CH_2 \buildrel{{t^o,P,xt}}\over\longrightarrow -(CH_2-CH=CH-CH_2)-_n$
3/
$nCH_2=CH_2 \buildrel{{t^o,P,xt}}\over\longrightarrow -(CH_2-CH_2)-_n$
$mC_2H_4=\frac{10}{80\%}=12,5kg$
