Đáp án:
Giải thích các bước giải:
Bài 1:
a) $\frac{-5}{7}$.$\frac{31}{33}$+$\frac{-5}{7}$.$\frac{2}{33}$+$\frac{22}{17}$
=$\frac{-5}{7}$.($\frac{31}{33}$+$\frac{2}{33}$)+$\frac{22}{17}$
=$\frac{-5}{7}$.$\frac{33}{33}$+$\frac{22}{17}$
=$\frac{-5}{7}$.1+$\frac{22}{17}$
=$\frac{-5}{7}$+$\frac{22}{17}$
=$\frac{-85}{119}$+ $\frac{154}{119}$
=$\frac{69}{119}$
b) $\frac{4}{7}$+$\frac{3}{7}$.($\frac{-2}{3}$)
=$\frac{7}{7}$.($\frac{-2}{3}$)
=1.($\frac{-2}{3}$)
=$\frac{-2}{3}$
c) $\frac{9².3³}{3^{7}}$
=$\frac{(3²)².3³ }{3^{7}}$
=$\frac{3^{4}.3^{3}}{3^{7}}$
=$\frac{3^{12}}{3^{7}}$
=$3^{5}$
d) 3-($\frac{7}{8}$)$^{0}$+($\frac{1}{2}$)$^{3}$.16
=3-(-1)+$\frac{1}{8}$.16
=4.$\frac{1}{8}$.16
=$\frac{4}{8}$.16
=4.2
=8
Bài 2:
a) $\frac{3}{5}$x+$\frac{2}{3}$= $\frac{4}{5}$
$\frac{3}{5}$x=$\frac{4}{5}$-$\frac{2}{3}$
$\frac{3}{5}$x=$\frac{12}{15}$-$\frac{10}{15}$
$\frac{3}{5}$x=$\frac{2}{15}$
x=$\frac{2}{15}$:$\frac{3}{5}$
x=$\frac{2}{15}$.$\frac{5}{3}$
x=$\frac{10}{45}$
