Đáp án:
\({{\text{V}}_{{C_2}{H_5}OH}} = 422,28{\text{ lít}}\)
Giải thích các bước giải:
\({({C_6}{H_{10}}{O_5})_n}\xrightarrow{{}}{C_6}{H_{12}}{O_6}\xrightarrow{{}}2{C_2}{H_5}OH\)
\( \to {m_{{C_6}{H_{10}}{O_5}}} = 1000.70\% = 700{\text{ kg}} \to {{\text{n}}_{{C_6}{H_{10}}{O_5}}} = \frac{{700}}{{162}} = 4,32{\text{ kmol}} \to {{\text{n}}_{{C_2}{H_5}OH\;{\text{lý thuyết}}}} = 4,32.2 = 8,64\;{\text{kmol}}\)
\({n_{{C_2}{H_5}OH{\text{ thực tế}}}} = 8,64.85\% = 7,344{\text{ kmol}} \to {{\text{m}}_{{C_2}{H_5}OH}} = 7,344.46 = 337,824\;{\text{kg}} \to {{\text{V}}_{{C_2}{H_5}OH}} = \frac{{337,824}}{{0,8}} = 422,28{\text{ lít}}\)
