\(\begin{array}{l} 1)\\ {C_2}{H_4} + {H_2}O \to {C_2}{H_5}OH\\ {C_2}{H_5}OH + {O_2} \to C{H_3}COOH + {H_2}O\\ C{H_3}COOH + {C_2}{H_5}OH \to C{H_3}COO{C_2}{H_5}\\ 2)\\ a)\\ nC{O_2} = \dfrac{{44}}{{44}} = 1\,mol \Rightarrow nC = 1\,mol\\ n{H_2}O = \dfrac{{27}}{{18}} = 1,5\,mol \Rightarrow nH = 3\,mol\\ mO = 23 - 1 \times 12 - 3 = 8g\\ nO = \dfrac{8}{{16}} = 0,5\,mol\\ = > A:C,H,O\\ b)\\ nC:nH:nO = 1:0,3:0,5 = 2:6:1\\ \Rightarrow CTDGN:{C_2}{H_6}O\\ MA = 23 \times 2 = 46g/mol\\ 46n = 46 \Rightarrow n = 1\\ CTPT:{C_2}{H_6}O\\ \end{array}\)
