Em tham khảo nha:
\(\begin{array}{l}
1)\\
{m_A} = 0,8 \times 32 + 0,2 \times 44 + 2 \times 16 = 66,4g\\
2)\\
a)\\
4Na + {O_2} \xrightarrow{t^0} 2N{a_2}O\\
N{a_2}O + {H_2}O \to 2NaOH\\
2NaOH + S{O_2} \to N{a_2}S{O_3} + {H_2}O\\
N{a_2}S{O_3} + BaC{l_2} \to 2NaCl + BaS{O_3}\\
BaS{O_3} + 2HCl \to BaC{l_2} + S{O_2} + {H_2}O\\
2NaOH + S{O_2} \to N{a_2}S{O_3} + {H_2}O\\
N{a_2}S{O_3} + {H_2}S{O_4} \to N{a_2}S{O_4} + S{O_2} + {H_2}O\\
N{a_2}S{O_4} + BaC{l_2} \to 2NaCl + BaS{O_4}\\
b)\\
S + {O_2} \xrightarrow{t^0} S{O_2}\\
S{O_2} + B{r_2} + 2{H_2}O \to 2HBr + {H_2}S{O_4}\\
CuO + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
CuS{O_4} + Fe \to FeS{O_4} + Cu\\
2FeS{O_4} + 2{H_2}S{O_4} \to F{e_2}{(S{O_4})_3} + S{O_2} + 2{H_2}O\\
F{e_2}{(S{O_4})_3} + 6NaOH \to 2Fe{(OH)_3} + 3N{a_2}S{O_4}\\
2FeC{l_2} + C{l_2} \to 2FeC{l_3}\\
FeC{l_3} + 3AgN{O_3} \to Fe{(N{O_3})_3} + 3AgCl
\end{array}\)
