a/8x(x+5)-x(3+8x)=16 a/(2xy-3x^2+5y)1/3xy^2
=>8x^2+40x-3x-8x^2=16 =2/3x^2y^3-x^3y^2+5/3xy^3
=>37x=16 b/(x^2-6xy+y^2)(1/3xy^2-y)
=>x=16/37 =1/3x^3y^2-2x^2y^3+1/3xy^4-x^2y+6xy^2-y^3
b/x(x+5)-(x-4)(x+4)=6 c/(x-2)(x+2)-(x-2)^2
=>x^2+5x-x^2+16=6 =x^2-4-x^2-4
=>5x=-10 =-8
=>x=-2 d/(x+3)(x^2-3x+9)-(x^3-1)
=x^3-3x^2+9x+3x^2-9x+27-x^3+1
=28