Đáp án:
\(\begin{array}{l}
x = 19,5\\
y = 4,38
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
{n_{{H_2}}} = \dfrac{V}{{22,4}} = \dfrac{{6,72}}{{22,4}} = 0,3\,mol\\
{n_{Zn}} = {n_{{H_2}}} = 0,3\,mol\\
x = {m_{Zn}} = n \times M = 0,3 \times 65 = 19,5g\\
{n_{HCl}} = 2{n_{{H_2}}} = 0,6\,mol\\
{m_{HCl}} = n \times M = 0,6 \times 36,5 = 21,9g\\
y = {C_\% }{\rm{dd}}HCl = \dfrac{{{m_{ct}}}}{{{m_{{\rm{dd}}}}}} \times 100\% = \dfrac{{21,9}}{{500}} \times 100\% = 4,38\%
\end{array}\)
