Đáp án:
\(\left[ \begin{array}{l}
m = 0\\
m = 3
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
C6:\\
Xét:\Delta ' \ge 0\\
\to {m^2} - 4m + 3 \ge 0\\
\to \left( {m - 3} \right)\left( {m - 1} \right) \ge 0\\
\to \left[ \begin{array}{l}
m \ge 3\\
m \le 1
\end{array} \right.\\
Do:{x_1}^2 + {x_2}^2 = 6\\
\to {x_1}^2 + {x_2}^2 + 2{x_1}{x_2} - 2{x_1}{x_2} = 6\\
\to {\left( {{x_1} + {x_2}} \right)^2} - 2{x_1}{x_2} = 6\\
\to 4{m^2} - 2\left( {4m - 3} \right) = 6\\
\to 4{m^2} - 12m + 6 = 6\\
\to 4m\left( {m - 3} \right) = 0\\
\to \left[ \begin{array}{l}
m = 0\\
m = 3
\end{array} \right.\left( {TM} \right)
\end{array}\)
