Đáp án:
\(\begin{array}{l}
a)\\
\% {V_{{C_2}{H_2}}} = 50\% \\
\% {V_{C{H_4}}} = 50\% \\
b)\\
{V_{C{O_2}}} = 36c{m^3}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
7)\\
a)\\
2{C_2}{H_2} + 5{O_2} \to 4C{O_2} + 2{H_2}O\\
C{H_4} + 2{O_2} \to C{O_2} + 2{H_2}O\\
hh:{C_2}{H_2}(a\,c{m^3});C{H_4}(b\,c{m^3})\\
\left\{ \begin{array}{l}
a + b = 24\\
\frac{5}{2}a + 2b = 54
\end{array} \right.\\
\Rightarrow a = 12;b = 12\\
\% {V_{{C_2}{H_2}}} = \dfrac{{12}}{{24}} \times 100\% = 50\% \\
\% {V_{C{H_4}}} = 100 - 50 = 50\% \\
b)\\
{n_{C{O_2}}} = 2{n_{{C_2}{H_2}}} + {n_{C{H_4}}}\\
\Rightarrow {V_{C{O_2}}} = 2{V_{{C_2}{H_2}}} + {V_{C{H_4}}} = 2 \times 12 + 12 = 36c{m^3}
\end{array}\)
