Giải thích các bước giải:
\(\begin{array}{l}
1.\\
a)MgC{l_2} + 2KOH \to Mg{(OH)_2} + 2KCl\\
b)\\
{m_{MgC{l_2}}} = \dfrac{{200 \times 20\% }}{{100\% }} = 40g\\
\to {n_{MgC{l_2}}} = 0,42mol\\
{m_{{\rm{dd}}KOH}} = 500 \times 1,1 = 550g\\
\to {n_{KOH}} = 2{n_{MgC{l_2}}} = 0,84mol\\
\to C{M_{KOH}} = \dfrac{{0,84}}{{0,5}} = 1,68M\\
c)\\
{n_{KCl}} = 2{n_{MgC{l_2}}} = 0,84mol \to {m_{KCl}} = 62,58g\\
{n_{Mg{{(OH)}_2}}} = {n_{MgC{l_2}}} = 0,42mol \to {m_{Mg{{(OH)}_2}}} = 24,36g\\
d)\\
{m_{{\rm{dd}}}} = {m_{{\rm{dd}}MgC{l_2}}} + {m_{{\rm{dd}}KOH}} - {m_{Mg{{(OH)}_2}}} = 725,64g\\
\to C{\% _{KCl}} = \dfrac{{62,58}}{{725,64}} \times 100\% = 8,62\% \\
2.\\
CuC{l_2} + 2NaOH \to Cu{(OH)_2} + 2NaCl\\
a)\\
{m_{CuC{l_2}}} = \dfrac{{200 \times 6,75\% }}{{100\% }} = 13,5g\\
\to {n_{CuC{l_2}}} = 0,1mol\\
\to {n_{Cu{{(OH)}_2}}} = {n_{CuC{l_2}}} = 0,1mol \to {m_{Cu{{(OH)}_2}}} = 9,8g\\
b)\\
{n_{NaCl}} = 2{n_{CuC{l_2}}} = 0,2mol \to {m_{NaCl}} = 11,7g\\
{m_{{\rm{dd}}}} = {m_{{\rm{dd}}CuC{l_2}}} + {m_{{\rm{dd}}NaOH}} - {m_{Cu{{(OH)}_2}}} = 300g\\
\to C{\% _{KCl}} = \dfrac{{11,7}}{{300}} \times 100\% = 3,9\% \\
c)\\
Cu{(OH)_2} \to CuO + {H_2}O\\
{n_{CuO}} = {n_{Cu{{(OH)}_2}}} = 0,1mol \to {m_{CuO}} = 8g\\
\end{array}\)
