Đáp án:
\(\begin{array}{l}
a)\\
{C_M}C{H_3}COOH = 0,4M\\
b)\\
{V_{{H_2}}} = 0,112l\\
c)\\
{V_{{\rm{dd}}NaOH}} = 0,2l
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
2C{H_3}COOH + 2Na \to 2C{H_3}COONa + {H_2}\\
{n_{C{H_3}COONa}} = \dfrac{{0,82}}{{82}} = 0,01\,mol\\
{n_{C{H_3}COOH}} = {n_{C{H_3}COONa}} = 0,01\,mol\\
{C_M}C{H_3}COOH = \dfrac{{0,01}}{{0,025}} = 0,4M\\
b)\\
{n_{{H_2}}} = \dfrac{{0,01}}{2} = 0,005\,mol\\
{V_{{H_2}}} = 0,005 \times 22,4 = 0,112l\\
c)\\
C{H_3}COOH + NaOH \to C{H_3}COONa + {H_2}O\\
{n_{NaOH}} = {n_{C{H_3}COOH}} = 0,01\,mol\\
{V_{{\rm{dd}}NaOH}} = \dfrac{{0,01}}{{0,05}} = 0,2l
\end{array}\)
