Đáp án:
Giải thích các bước giải:
1 )
($\frac{-1}{3}$)^3 = $\frac{-1^3}{3^3}$ = $\frac{-1}{27}$
$(-0,3)^{2}$ = ($\frac{-3}{10}$)^2 = $\frac{-3^2}{10^2}$ = $\frac{9}{100}$
(-5$\frac{1}{2}$)^0 = 1
($\frac{-1}{2}$)^4 = $\frac{-1^4}{2^4}$ = $\frac{1}{16}$
3 )
a . ($\frac{1}{3}$)^n = $\frac{1}{27}$ → ($\frac{1}{3}$)^n = ($\frac{1}{3}$)^3 → n = 3
b . ($\frac{3}{5}$)^n = $\frac{81}{625}$ → ($\frac{3}{5}$)^n = ($\frac{3}{5}$)^4 → n = 4
c . $3^{n}$ . $2^{n}$ = 36 → $6^{n}$ = $6^{2}$ → n = 2
d . $\frac{2^n}{3^n}$ = $\frac{8}{27}$ → $\frac{2^n}{3^n}$ =$\frac{2^3}{3^3}$ → n = 3
