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`1, |x|=0`
`<=> x = 0`
Vậy `S={0}`
`2, |x|=1,375`
\(⇔\left[ \begin{array}{l}x=1,375\\x=-1,375\end{array} \right.\)
Vậy `S={1,375;-1,375}`
`3, |x| =1/5`
\(⇔\left[ \begin{array}{l}x=\dfrac15\\x=-\dfrac15\end{array} \right.\)
Vậy `S={1/5;-1/5}`
`4, |x+3/4| -1/2 = 0`
`<=> |x+3/4| = 1/2`
\(⇔\left[ \begin{array}{l}x+\dfrac34=\dfrac12\\x+\dfrac34=-\dfrac12\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=-\dfrac14\\x=-\dfrac54\end{array} \right.\)
Vậy `S={-1/4;-5/4}`
`5,|x-2/5|=1/4`
\(⇔\left[ \begin{array}{l}x-\dfrac25=\dfrac14\\x-\dfrac25=-\dfrac14\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=\dfrac{13}{20}\\x=-\dfrac3{20}\end{array} \right.\)
Vậy `S={13/20;-3/20}`
`6,1/5 + |x-13/10| = 3/2`
`<=> |x-13/10|=3/2-1/5`
`<=> |x-13/10|=13/10`
\(⇔\left[ \begin{array}{l}x-\dfrac{13}{10}=\dfrac{13}{10}\\x-\dfrac{13}{10}=-\dfrac{13}{10}\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=\dfrac{13}{5}\\x=0\end{array} \right.\)
Vậy `S={13/5;0}`
`7, 2|2x-3|=1/2`
`<=> |2x-3|=1/2:2`
`<=> |2x-3|=1/4`
\(⇔\left[ \begin{array}{l}2x-3=\dfrac{1}{4}\\2x-3=-\dfrac{1}{4}\end{array} \right.\)
\(⇔\left[ \begin{array}{l}2x=\dfrac{13}{4}\\2x=\dfrac{11}{4}\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=\dfrac{13}{8}\\x=\dfrac{11}{8}\end{array} \right.\)
Vậy `S={13/8;11/8}`
`8, 3,6 - |x-0,4| = 0`
`<=> 3,6 - 0 = |x-0,4|`
`<=> |x-0,4| = 3,6`
\(⇔\left[ \begin{array}{l}x-0,4=3,6\\x-0,4=-3,6\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=4\\x=-3,2\end{array} \right.\)
Vậy `S={4;-3,2}`
`9, 2|x-3,5|=1/2`
`<=> |x-3,5|=1/4`
\(⇔\left[ \begin{array}{l}x-3,5=\dfrac{1}{4}\\x-3,5=-\dfrac{1}{4}\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=\dfrac{15}{4}\\x=\dfrac{13}{4}\end{array} \right.\)
Vậy `S={15/4;13/4}`
`10,|3/4-1/2x|+1/3=5/6`
`<=> |3/4-1/2x| = 5/6-1/3`
`<=> |3/4-1/2x| = 1/2`
\(⇔\left[ \begin{array}{l}\dfrac34-\dfrac12x=\dfrac{1}{2}\\\dfrac34-\dfrac12x=-\dfrac{1}{2}\end{array} \right.\)
\(⇔\left[ \begin{array}{l}\dfrac12x=\dfrac{1}{4}\\\dfrac12x=\dfrac{5}{4}\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=\dfrac{1}{2}\\x=\dfrac{5}{2}\end{array} \right.\)
Vậy `S={1/2;5/2}`