Đáp án:
Phản ứng xảy ra:
\[2C_4H_{10}+13O_2\to 8CO_2+10H_2O\]
\[n_{C_4H_{10}}=\dfrac{12,5}{58}=\dfrac{25}{116}(mol)\]
\[n_{O_2}=\dfrac{13}{2}.n_{C_4H_{10}}=\dfrac{13}{2}.\dfrac{25}{116}=1,4(mol)\]
\[\to V_{O_2}=1,4.22,4=31,36(l)\]
\[\to V_{kk}=\dfrac{31,36}{20\%}=156,8(l)\]
\[n_{CO_2}=4.n_{C_4H_{10}}=4.\dfrac{25}{116}=\dfrac{25}{29}(mol)\]
\[\to V_{CO_2}=22,4.\dfrac{25}{29}=19,31(l)\]
