Đáp án:
$a) 2^{8}$
$b) 2^{18}$
$c)-\dfrac{5}{7}$
Giải thích các bước giải:
$a) (2^{2})^{(2^{2})}=4^{4}=(2^{2})^{4}=2^{8}\\b) \dfrac{8^{14}}{4^{12}}=\dfrac{(2^{3})^{14}}{(2^{2})^{12}}=\dfrac{2^{42}}{2^{24}}=2^{18}\\c) \dfrac{\left ( -\dfrac{5}{7} \right )^{n+1}}{\left ( -\dfrac{5}{7} \right )^{n}}(n\geq 1)\\=\dfrac{\left ( -\dfrac{5}{7} \right )^{n}.\left ( -\dfrac{5}{7} \right )}{\left ( -\dfrac{5}{7} \right )^{n}}=-\dfrac{5}{7}$