Bạn tham khảo nhé:
1/$\frac{3}{x+4}$=5
⇔$ 5(x+4)$ =3
⇔$ 5x+20=3$
⇔$ 5x=-17$
⇔$ x=$ $\frac{-17}{5}$
2/$\frac{-2x+1}{4x+2}$ =$ -3$
⇔$ -2x+1$ =$ -3(4x+2)$
⇔$ -2x+1$ =$ -12x-6$
⇔$ 10x$ =$ -7$
⇔$ x$ = $\frac{-7}{10}$
3/$\frac{1-2x}{x+2}$+ $\frac{x}{x-1}$=$-1$
⇔$\frac{-x^2+3x-1}{(x-2)(x-1)}$+$1$=$ 0$
⇔$\frac{-x^2+3x-1+x^2+x-2}{(x-2)(x-1)}$=$0$
⇔$\frac{6x-3}{(x+2)(x-1)}$=$0$
⇔$ 6x-3$ =$ 0$
⇔$ x$ =$\frac{1}{2}$