Giải thích các bước giải:
$VT=64\sqrt{3}\sin\dfrac{\pi}{64}\cos\dfrac{\pi}{64}\cos\dfrac{\pi}{32}\cos\dfrac{\pi}{16}\cos\dfrac{\pi}{8}\\
=64\sqrt{3}.\dfrac{1}{2}\sin\dfrac{2.\pi}{64}\cos\dfrac{\pi}{32}\cos\dfrac{\pi}{16}\cos\dfrac{\pi}{8}\\
=32\sqrt{3}\sin\dfrac{\pi}{32}\cos\dfrac{\pi}{32}\cos\dfrac{\pi}{16}\cos\dfrac{\pi}{8}\\
=32\sqrt{3}.\dfrac{1}{2}\sin\dfrac{2.\pi}{32}\cos\dfrac{\pi}{16}\cos\dfrac{\pi}{8}\\
=16\sqrt{3}\sin\dfrac{\pi}{16}\cos\dfrac{\pi}{16}\cos\dfrac{\pi}{8}\\
=16\sqrt{3}.\dfrac{1}{2}\sin\dfrac{2.\pi}{16}\cos\dfrac{\pi}{8}\\
=8\sqrt{3}\sin\dfrac{\pi}{8}\cos\dfrac{\pi}{8}\\
=8\sqrt{3}.\dfrac{1}{2}\sin\dfrac{2.\pi}{8}\\
=4\sqrt{3}\sin\dfrac{\pi}{4}\\
=4\sqrt{3}.\dfrac{\sqrt{2}}{2}\\
=2\sqrt{6}$
