Em tham khảo nha :
\(\begin{array}{l}
1)\\
NaOH + HCl \to NaCl + {H_2}O\\
NaOH + S{O_2} \to NaHS{O_3}\\
2NaOH + S{O_2} \to N{a_2}S{O_3}\\
N{a_2}S{O_3} + 2HCl \to 2NaCl + S{O_2} + {H_2}O\\
S{O_2} + Ba{(OH)_2} \to BaS{O_3} + {H_2}O\\
2)\\
MgS{O_3} + 2HCl \to MgC{l_2} + S{O_2} + {H_2}O\\
MgC{O_3} + 2HCl \to MgC{l_2} + C{O_2} + {H_2}O\\
hh:MgS{O_3}(a\,mol),MgC{O_3}(b\,mol)\\
104a + 84b = 38,6(1)\\
64a + 44b = 22,6(2)\\
\text{Từ (1) và (2)}\Rightarrow a = 0,25;b = 0,15\\
{n_{MgC{l_2}}} = {n_{MgS{O_3}}} + {n_{MgC{O_3}}} = 0,25 + 0,15 = 0,4mol\\
{m_{MgC{l_2}}} = 0,4 \times 95 = 38g\\
{m_{ddspu}} = 38,6 + 600 - 22,6 = 616g\\
C{\% _{MgC{l_2}}} = \dfrac{{38}}{{616}} \times 100\% = 6,17\%
\end{array}\)
