Đáp án:
\(\begin{array}{l}
a)x = 37\\
b)\left[ \begin{array}{l}
x = \dfrac{{17}}{6}\\
x = \dfrac{1}{2}
\end{array} \right.\\
c)x = \dfrac{{359}}{{60}}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)DK:x \ne - 5\\
\dfrac{{x - 1}}{{x + 5}} = \dfrac{6}{7}\\
\to 7x - 7 = 6x + 30\\
\to x = 37\\
b)\left| {x - \dfrac{5}{3}} \right| = \dfrac{7}{6}\\
\to \left[ \begin{array}{l}
x - \dfrac{5}{3} = \dfrac{7}{6}\left( {DK:x \ge \dfrac{5}{3}} \right)\\
x - \dfrac{5}{3} = - \dfrac{7}{6}\left( {DK:x < \dfrac{5}{3}} \right)
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \dfrac{{17}}{6}\\
x = \dfrac{1}{2}
\end{array} \right.\\
c)\dfrac{{33}}{4} - x = \dfrac{{19}}{6} - \dfrac{9}{{10}}\\
\to \dfrac{{33}}{4} - x = \dfrac{{34}}{{15}}\\
\to x = \dfrac{{359}}{{60}}
\end{array}\)
