Đáp án:
Giải thích các bước giải:
$n_{Zn}=\dfrac{m_{Zn}}{M_{Zn}}=\dfrac{19,5}{65}=0,3 \ (mol)$
a,
$PTHH:2Zn+O_2\xrightarrow{t^o}2ZnO$
b,
$Theo \ PTHH:n_{ZnO}=n_{Zn}=0,3 \ (mol)$
$m_{ZnO}=n_{ZnO}.M_{ZnO}=0,3.81=24,3 \ (g)$
c,
$Theo \ PTHH:n_{O_2}=\dfrac12n_{Zn}=\dfrac12.0,3=0,15 \ (mol)$
$V_{O_2}=n_{O_2}.22,4=0,15.22,4=3,36 \ (l)=3360 \ (ml)$
d,
$PTHH:2KClO_3\xrightarrow{t^o}2KCl+3O_2$
$Theo \ PTHH:n_{KClO_3}=\dfrac23n_{O_2}=\dfrac23.0,15=0,1 \ (mol)$
$m_{KClO_3}=n_{KClO_3}.M_{KClO_3}=0,1.122,5=12,25 \ (g)$
