Em tham khảo nha:
\(\begin{array}{l}
a)\\
CTHH\,:A{H_3}\\
{M_X} = 17\,dvC \Rightarrow {M_A} + 1 \times 3 = 17\\
\Rightarrow {M_A} = 17 - 3 = 14\,dvC \Rightarrow A:Nito(N)\\
CTHH\,X:N{H_3}\\
b)\\
0,425{M_Y} = {M_X} \Rightarrow {M_Y} = \dfrac{{{M_X}}}{{0,425}} = \dfrac{{17}}{{0,425}} = 40\,dvC\\
CTHH\,Y:B{(OH)_b}\\
{M_Y} = 40g/mol \Rightarrow {M_B} + 17b = 40g\\
b = 1 \Rightarrow {M_B} = 23\,dvC \Rightarrow B:Natri(Na)\\
b = 2 \Rightarrow {M_B} = 6dvC\\
b = 3 \Rightarrow {M_B} = - 11\\
CTHH\,Y:NaOH
\end{array}\)
