Trả lời :
B1: d.
\[\begin{array}{I}\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{43.45}\\=\frac{2}{5}-\frac{2}{7}+\frac{2}{7}-\frac{2}{9}+\frac{2}{9}-\frac{2}{11}+...+\frac{2}{43}-\frac{2}{45}\\=\frac{2}{5}-\frac{2}{45}\\=\frac{18}{45}-\frac{2}{45}=\frac{16}{45}\end{array}\]
B2 : d.
\[\begin{array}{I}(x-1)^2=25\\\Leftrightarrow (x-1)^2=5^2=-5^2\\\Rightarrow x-1=5 hoặc x-1=-5\\\Rightarrow x=5+1=6; x=-5+1=-4\end{array}\]
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