Đáp án:
\(\begin{array}{l}
a)\\
CTPT:{C_3}{H_6}\\
b)\\
CTCT:\\
C{H_2} = CH - C{H_3}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
CTPT:{C_x}{H_y}\\
{n_{C{O_2}}} = \dfrac{{20,16}}{{22,4}} = 0,9mol\\
{n_C} = {n_{C{O_2}}} = 0,9mol\\
{n_{{H_2}O}} = \frac{{16,2}}{{18}} = 0,9mol\\
{n_H} = 2{n_{{H_2}O}} = 1,8mol\\
x = \dfrac{{{n_C}}}{{{n_A}}} = \frac{{0,9}}{{0,3}} = 3\\
y = \dfrac{{{n_H}}}{{{n_A}}} = \frac{{1,8}}{{0,3}} = 6\\
\Rightarrow CTPT:{C_3}{H_6}\\
b)\\
CTCT:\\
C{H_2} = CH - C{H_3}
\end{array}\)
