Đáp án: `A=15 \ MJ`
Tóm tắt:
`F=5000N`
`s=3000m`
----------------
`A=?`
Giải:
Công lực kéo của đầu tàu hỏa `A` là:
`A=Fs=5000.3000=15000000 \ (J)=15 \ MJ`
Đáp án:
Giải thích các bước giải:
Tóm tắt :
`F = 5000 N`
`s = 3000 m`
`A = ?`
Giải
Công lực kéo của đầu tàu hoả A :
`A = F . s = 5000 . 3000 = 15000000 (J)`
phân tích thành nhân tử giúp em với ạ a)X2 +5x+5y+2xy+y2 b) x2 – 16-2xy +y2
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