Đặt n C2H4 = a(mol); n C2H2 = b(mol)
PTHH: C2H4+Br2 -> C2H4Br2
(mol)____a____a___________a______
PTHH: C2H2 + 2Br2-> C2H2Br4
(mol)____b______2b________b___
Theo đề bài ta có hpt:
a+b=6,72/22,4
a+2b=64/160
=> a=0,2;b=0,1
%V C2H4 = (0,2.22,4)/6,72 .100%=66,7(%)
=> %V C2H2 = 100-66,7=33,3(%)