Đáp án:
\(\begin{array}{l}
a)\\
CTHH:{H_2}S\\
b)\\
\% {m_{Cu}} = 40\% \\
\% {m_S} = 20\% \\
\% {m_O} = 40\%
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
\% {m_H} = 100 - 94,118 = 5,882\% \\
CTHH:{H_x}{S_y}\\
x:y = \dfrac{{5,882}}{1}:\dfrac{{94,118}}{{32}} = 2:1\\
\Rightarrow CTHH:{H_2}S\\
b)\\
\% {m_{Cu}} = \dfrac{{64}}{{160}} \times 100\% = 40\% \\
\% {m_S} = \dfrac{{32}}{{160}} \times 100\% = 20\% \\
\% {m_O} = 100 - 40 - 20 = 40\%
\end{array}\)