a.
$W_A=Wđ_A+Wt_A=0+mgh_A$
$=>W_A=1.10.0,05=0,5(J)$
b.
$Wđ_B-Wđ_A=A_N+A_P$
$<=>\dfrac{1}{2}mv_B^2-\dfrac{1}{2}mv_A^2=mgh$
$<=>\dfrac{1}{2}.v_B^2=10.0,05$
$=>v_B=1(m/s)$
c.
$Wđ_C-Wđ_B=A_N+A_P+A_{Fms}$
$<=>\dfrac{1}{2}mv_C^2-\dfrac{1}{2}mv_B^2=-μmgs$
$<=>-\dfrac{1}{2}=-μ.10.4$
$=>μ=0,0125$