Giải thích các bước giải:
a.x=0,73cmb.FA=3,84Nc.Vchi=6,8.10−5m3a.x=0,73cmb.FA=3,84Nc.Vchi=6,8.10−5m3
Giải thích các bước giải:
P=FA10.DvatV=dnuocV′10.750.0,083=10000.(0,08−x)3x=0,0073m=0,73cmb.FA=P=10.750.0,083=3,84Nc.Vvat=V−VchimvatD=0,083−Vchimvat=750(0,083−Vchi)m′=mvat+mchi=750(0,083−Vchi)+DchiVchi=750(0,083−Vchi)+11300VchiP′=FA10m′=dnV10.750(0,083−Vchi)+11300Vchi=10000.0,083Vchi=6,8.10−5m3P=FA10.DvatV=dnuocV′10.750.0,083=10000.(0,08−x)3x=0,0073m=0,73cmb.FA=P=10.750.0,083=3,84Nc.Vvat=V−VchimvatD=0,083−Vchimvat=750(0,083−Vchi)m′=mvat+mchi=750(0,083−Vchi)+DchiVchi=750(0,083−Vchi)+11300VchiP′=FA10m′=dnV10.750(0,083−Vchi)+11300Vchi=10000.0,083Vchi=6,8.10−5m3