Đáp án:
$\begin{array}{l}
a.{{\rm{W}}_d} = 0\\
{{\rm{W}}_t} = 200\left( J \right)\\
{\rm{W}} = 200\left( J \right)\\
b.{v_1} = 10\sqrt 2 = 14,14\left( {m/s} \right)\\
c.{z_2} = \frac{z}{4} = 2,5\left( m \right)
\end{array}$
Giải thích các bước giải:
$\begin{array}{l}
a.{{\rm{W}}_d} = \frac{1}{2}m{v^2} = 0\\
{{\rm{W}}_t} = mgz = 2.10.10 = 200\left( J \right)\\
{\rm{W}} = {{\rm{W}}_d} + {{\rm{W}}_t} = 200\left( J \right)\\
b.{{\rm{W}}_{d1}} = {\rm{W}}\\
\Rightarrow \frac{1}{2}mv_1^2 = {\rm{W}}\\
\Rightarrow \frac{1}{2}.2.v_1^2 = 200\\
\Rightarrow {v_1} = 10\sqrt 2 = 14,14\left( {m/s} \right)\\
c.{{\rm{W}}_{d2}} = 3{W_{t2}}\\
\Rightarrow {{\rm{W}}_{t2}} = \frac{{\rm{W}}}{4}\\
\Rightarrow {z_2} = \frac{z}{4} = 2,5\left( m \right)
\end{array}$