\(\begin{array}{l}
{C_{12}}{H_{22}}{O_{11}} + {H_2}O \to {C_6}{H_{12}}{O_6} + {C_6}{H_{12}}{O_6}\\
n{C_6}{H_{12}}{O_6} = \dfrac{{1462,5}}{{180}} = 8,125\,mol\\
n{C_{12}}{H_{22}}{O_{11}} = n{C_6}{H_{12}}{O_6} = 8,125\,mol\\
m{C_{12}}{H_{22}}{O_{11}} = 8,125 \times 342 = 2778,75g
\end{array}\)